2x^2+7x+7=(2x-1)(x+3)

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Solution for 2x^2+7x+7=(2x-1)(x+3) equation: 



2x^2+7x+7=(2x-1)(x+3)

We move all terms to the left:

2x^2+7x+7-((2x-1)(x+3))=0

We multiply parentheses ..

2x^2-((+2x^2+6x-1x-3))+7x+7=0



We calculate terms in parentheses: -((+2x^2+6x-1x-3)), so:

(+2x^2+6x-1x-3)

We get rid of parentheses

2x^2+6x-1x-3

We add all the numbers together, and all the variables

2x^2+5x-3

Back to the equation:

-(2x^2+5x-3)



We add all the numbers together, and all the variables

2x^2+7x-(2x^2+5x-3)+7=0

We get rid of parentheses

2x^2-2x^2+7x-5x+3+7=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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